Question

hyy ananya kya tum isko solve kr skti ho
agar aa rha h to solve kro
aur tom tum bhi​

Answer 1

HERE IS YOUR ANSWER:-

In triangle ADE

angle (DAE+ADE+DEA)=180°

angle(42°+86°+DEA)=180°

angle(128°+DEA)=180°

angle DEA=180°-128°

angle DEA=52°

Now, In right - angled ∆ triangle CFE

angle(CFE+ CEF +ECF)= 180°

angle(90°+52°+ECF)= 180°

angle(142°+ECF)=180°

angle ECF= 180°-142°

angle ECF= 38°

Hence the required value of angle ECF is 38°.

Hope it will help you.