Question

Hyy....plz answer----

Find the probability of tossing the dice twice and getting the same number both the times....

** I m not sure that's why I asked**

Answer 1

total outcomes =36
favourable outcomes =6((1,1)(2,2)(3,3)(4,4)(5,5)(6,6))
probability =favourable outcomes/total outcomes
6/36=1/6=0.166
HOPE THIS HELPS U

Answer 2

TOTAL POSSIBLE OUTCOMES tossing 2,dice at a 1 time = 36

(1,1)(1,2)(1,3)..............

..............................,............(6,4)(6,5)(6,6)

Number of events in which both the outcomes coincide that is both the dice shows the same number = (1,1)(2,2)(3,3)(4,4)(5,5)(6,6)

that is 6 events out of 36 SAMPLE SPACE

PROBABILITY = FAVORABLE OUTCOMES ÷ TOTAL OUTCOMES

$= \frac{6}{36}$

= 1/6 = 0.167

HOPE IT HELPS ;-)
is the requried answer