Question

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Answer 1

The average power (often simply called "power" when the context makes it clear) is the average amount of work done or Energy transferred per unit time follow me plz

Answer 2

The energy possesses on a motional body called k. E

Derivation K. E= 1/2mv²

Work(W) = K. E

W= F×S----------1 eq.

Apply second eq. Of newton

F=ma-------2eq.

Apply 3rd eq. Of motion

V²=U²+2as

U = O

V²= 2as

S= V²/2a---------3eq

Putting 3eq and 2eq in first eq.

Then

W= ma×v²/2a

W= mv²/2a

Work= k. E

K. E= 1/2mv²

Ans2.... 20Hz to 20,000Hz

Ans3 rate of doing work of a body called power

S. I unit= watt

Ans 4 kwh and joule

1kwh= 1000w×3600sec

But 1W=1j/sec

1kwh= 1000j/sec×3600sec

Then

1Kwh = 1000×3600 j

= 3600000j

3.6×10power6 joule