Math, asked by siu58, 10 months ago

hyyyy solution plzzz​

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Answered by CrimsonLotus
2

That's the answer hope it helps you. GO BANKAI

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Answered by sagarmankoti
1

 \:  \:  \:  \:  \frac{4}{3 \sqrt{3} - 2 \sqrt{2}  }  +  \frac{3}{3 \sqrt{3}   +  2 \sqrt{2} }  \\  =  \frac{4(3 \sqrt{3}  + 2 \sqrt{2} ) + 3(3 \sqrt{3}  - 2 \sqrt{2} }{(3 \sqrt{3}  - 2 \sqrt{2})(3 \sqrt{3} + 2 \sqrt{2}  )}  \\  =  \frac{12 \sqrt{3 }  + 8 \sqrt{2}  + 9 \sqrt{2} - 6 \sqrt{2}  }{ {(3 \sqrt{3}) }^{2} -  {(2 \sqrt{2} )}^{2}  }  \\  =  \frac{21 \sqrt{3}  + 3 \sqrt{2} }{27- 8}  \\  =  \frac{3(7 \sqrt{3}  +  \sqrt{2}) }{19}


sagarmankoti: Sorry the answer is (21√3+2√2)÷19
CrimsonLotus: what have i written then
CrimsonLotus: check once
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