(i) (1 - 256x4) = (1 + 16x²)
solve the expression
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calculate the (H3O+) &(OH-) at 298k in ..
(I) 0.01 M HCL
(II) 0.005 MNAOH ..Given, 0.6x+0.8=0.28x+1.16
or 0.6x−0.28x=1.16−0.8 ...[Transposing 0.28x to LHS and 0.8 to RHS ]
or 0.32x=0.36
⟹
100
32x
=
100
36
⟹32x=36
⟹x=
32
36
⟹x=
8
9
[DividingnumeratoranddenominatoronRHSby4
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