(i) 1.5M
(ii) 1.66 M
4. The number of atoms present in one mole of an element is equal to Avogadro number.
Which of the following element contains the greatest number of atoms?
(iv) 12g He
4. He (11) 46g Na (ii) 0.40g Ca
11 what will be the
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Answer:
4:(2=1.66M
4.46g Na
Explanation:
I Think It's Ryt answer
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