Question

(i) (1 + tan + sec 0) (1 + cot - cosec ) =?​

Answer 1

Answer:

hope this will help you

Answer 2

Answer:

2 is the answer

Step-by-step explanation:

• 1(1+cot- cosec) + tan(1+ cot -cosec) + sec(1+ cot- cosec)
• 1+ cot- cosec + tan + tancot - tancosec+ sec(1+ cot-cosec)
• 1+cot-cosec + tan +1 - sec+ sec+ secAcotA - secACosecA (substitute value of tan and cot )
• 1+ cot- cosec + tan +1 -sec + sec + cosec - cosecAsecA( Substitute value of sec and cosec)
• 2+ cot -cosec +tan + cosec - cosecAsecA

BY LCM

• 2+ cos/sin +sin/cos - 1/sincos
• 2+
• $2 + \frac{ \cos \: a ^{2} }{ sin \: a \: cos \: a } + \frac{ sin \: a ^{2} }{ \sin \: a \cos \: a} - \frac{1}{ \sin \: a \cos \: a }$
• 2+ 1-1/sinA cos A ( cos^2 + sin^2= 1)
• 2+ 0/sinA cosA
• 2+0

Therefore answer is 2

This is the correct answer

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