Math, asked by ankita18111997, 4 months ago

i) 100 less than the largest 4 digit numbers.

ii) 10 more than 4,309​

Answers

Answered by gamemaster1
3

Step-by-step explanation:

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Answered by halamadrid
1

i) 100 less than the largest 4-digit number is 9899 and ii) 10 more than 4,309 is 4319.

Given:

i) 100 less than the largest 4-digit numbers.

ii) 10 more than 4,309​.

To Find:

The values of:

i) 100 less than the largest 4-digit numbers.

ii) 10 more than 4,309​.

Solution:

i) A 4-digit number consists of four places: Thousands, hundreds, tens, and ones.

The largest 4-digit number can be found by placing 9 (the greatest digit) in all places.

Hence, the largest 4-digit number is 9999.

So, 100 less than the largest 4-digit number = 9999-100 = 9899.

Hence, 100 less than the largest 4-digit number is 9899.

ii) 10 more than 4,309​ can be found by adding 10 to 4,309.

10 + 4,309 = 4319.

Hence, 10 more than 4,309 is 4319.

∴ i) 100 less than the largest 4-digit number is 9899 and ii) 10 more than 4,309 is 4319.

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