Question

(i) 12,15 and 21 ii) 17,23 and 29
Given that HCF (306, 657) =9, find LCM (306,657).​

Answer 1

Answer:

LCM = 32538

Step-by-step explanation:

You know that

LCM × HCF = PRODUCT OF NUMBERS.

9 × LCM = 306 × 657

LCM = 306 × 657 / 9

LCM = 102 × 319

LCM = 32538

PLEASE MARK ME BRAINILEST.

Answer 2

:

Mark Me As Brainliest And Thank Me If The Answer Is Useful.

-- :

Using prime factorisation method:

(i) 12, 15 and 21

Factor of 12=2×2×3

Factor of 15=3×5

Factor of 21=3×7

HCF (12,15,21)=3

LCM (12,15,21)=2×2×3×5×7=420

(ii) 17, 23 and 29

Factor of 17=1×17

Factor of 23=1×23

Factor of 29=1×29

HCF (17,23,29)=1

LCM (17,23,29)=1×17×23×29=11,339

(iii) 8, 9 and 25

Factor of 8=2×2×2×1

Factor of 9=3×3×1

Factor of 25=5×5×1

HCF (8,9,25)=1

LCM (8,9,25)=2×2×2×3×3×5×5=1,800