Math, asked by eeeelol, 5 hours ago

(i) 12 x2 + 16y2 + 8z2 – 16√3 xy + 16 √2 yz – 8√6 xz

Answers

Answered by armangiri2013
0

Answer:

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Answered by nikhitaN
1

Answer:

(2√3x+4y-2√2z)^2

Step-by-step explanation:

(2√3x)^2+(4y)^2+(-2√2z)^2-2(2√3x)(4y)-2(4y)(-2√2z)-2(2√2z)(2√3x)

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