Math, asked by chahatagawala04, 2 months ago

(i) 1764 (i) 9216 (ii) 7744
(iv) 9801
(5) Find the least numbers (integer) with which the following numbers are
to be multiplied so that they become perfect squares.
(1) 1525 (ii) 1008
(ii) 2028 (iv) 768
mhom (integer) the following numbers are to be divided so​

Answers

Answered by ronaldoChristiano
2

\huge\mathfrak\pink{⭐Your ‎ ‎Answer⭐}

────────────────────

❤️Hello Dear❤️,

 ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ Thus, 2028 needs to be multiplied by 3 to become a perfect square. Therefore, the number 6084 has 3 pairs of equal prime factors . Hence, the smallest number by which 2028 must be multiplied so that the product is a perfect square is 7. And the square root of the new number is √6084=78

────────────────────

Hope you will mark as brainliest Follow back xd.

Similar questions