Question

i) 2 (a2 +b2) x2 + 2(a + b) x + 1 = 0
find the nature of roots​

Answer 1

Step-by-step explanation:

b²-4ac

[2(a+b)]²-4[2(a²+b²)][1]

4(a²+b²+2ab)-4[4(a²+b²+2ab)]

4a²+4b²+8ab-4(4a²+4b²+8ab)

4a²+4b²+8ab-16a²-16b²-32ab

4a²-16a²+4b²-16b²+8ab-32ab

-12a²-12b²-24ab

-12(a²+b²+2ab)

or -12(a+b)²