(i) 2 cos²ø+2/1+cot²ø
= 2
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Step-by-step explanation:
(Sorry thetta is not in my keyboard so I am using x)
L.H.S=2cos^2x + 2/1+cot^2x
=2cos^2x + 2/cosec^x
=2cos^2x +2 * sin^2x(1/cosec^2x = sin^2x)
=2(cos^2x + sin^2x)
=2(1) [sin^2x + cos^2x =1]
=2
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