(i) (2+i)x2 + (i - 5)x – 2(i-1) = 0
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ANSWER
Given,
(2+i)x
2
−(5−i)x+2(1−i)=0
(2+i)(a+bi)
2
−(5−i)(a+bi)+2(1−i)=0
(2a
2
−2b
2
−2ab−5a−b+2)+i(−2+a+a
2
−b
2
−5b+4ab)=0
(2a
2
−2b
2
−2ab−5a−b+2)+i(−2+a+a
2
−b
2
−5b+4ab)=0+0i
(2a
2
−2b
2
−2ab−5a−b+2)+i(−2+a+a
2
−b
2
−5b+4ab)=0+0i
solving the above 2 equations, we get,
(
a=1,
a=
5
4
,
b=−1
b=−
5
2
)
x=1−i,
5
4
−
5
2
i
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