Math, asked by shivamgamer32, 9 months ago

(i) 25√2 $ 6√2 (ii) 8√5 & 2√5

(iii) 9√3 & 3√3 (iv) 12√6 $ 18√6

(v) 17√11 $ 3√11 (vi) 7√3 & 6√3


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Answered by juhi0000
1

Answer:

hope it will help you ^_^

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Answered by mysticd
2

\red{ i) 25\sqrt{2} + 6 \sqrt{2}}

 = (25+6)\sqrt{2}

\green { = 31\sqrt{2} }

\red{ ii) 8\sqrt{5} - 2 \sqrt{5}}

 = (8-2)\sqrt{5}

\green { = 6\sqrt{5} }

\red{ iii) 9\sqrt{3} - 3 \sqrt{3}}

 = (9-3)\sqrt{3}

\green { = 6\sqrt{3} }

\red{ iv) 12\sqrt{6} + 18\sqrt{6}}

 = (12+18)\sqrt{6}

\green { = 30\sqrt{6} }

\red{ v) 17\sqrt{11} + 3 \sqrt{11}}

 = (17+3)\sqrt{11}

\green { = 20\sqrt{11} }

\red{ vi) 7\sqrt{3} - 6 \sqrt{3}}

 = (7-6)\sqrt{3}

\green { = \sqrt{3} }

•••♪

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