Question

i^29 + (1/i )^50 find in from of a+ib​

Answer 1

$i^{29}+\left(\dfrac{1}{i}\right)^{50}=(i^4)^7\cdot i+\dfrac{1}{i^{50}}=1\cdot i+\dfrac{1}{(i^4)^{12}\cdot i^2}=i+\dfrac{1}{1^{12}\cdot (-1)}=i+\dfrac{1}{-1}=-1+i$