Question

I = 2A , R = 6 Ohm , t = 5 min , the Heat = ?​

Answer 1

Answer:

Given: I=2.5A,R=20Ω,t=5×60=300s.

Heat Produced =(PotentialDifference)×(Current)×(time)

=VIt

=I

2

Rt (ohm's law, V=IR)

=

10

25

×

10

25

×20×300=37500J

=37.5kJ

Hence, 37.5 kJ heat is produced.