Math, asked by SubhalaxmiPrusty, 3 months ago

i- (2x+3y)²
ii- (3m-4n)²
iii- 201²​

Answers

Answered by subhangee1
2

Answer:

I. 4x²+12xy+9y²

II. 9m2-24mn+16n2

iii. 40401

Step-by-step explanation:

i.by the formula of (a+b)2=a²+2ab+b²

II. by the formula of (a-b)²=a²-2ab +b²

iii. 201×201=40401

Answered by diksha6305
1

Answer:

i- (2x+3y)

= Using Identity (a+b)²=a²+2ab+b²

= (2x)²+2(2x)(3y)+(3y)²

= 4x²+12xy+9y²

ii- (3m-4n)

Using Identity (a-b)²=a²-2ab+b²

=(3m)²-2(3m)(4n)+4n²

= 9m²-24mn+16n²

iii- 201²

=Using Identity 1st

=(200+1)²

=(200)²+2(200)(1)+(1)²

=40000+400+1

=40401

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