i- (2x+3y)²
ii- (3m-4n)²
iii- 201²
Answers
Answered by
2
Answer:
I. 4x²+12xy+9y²
II. 9m2-24mn+16n2
iii. 40401
Step-by-step explanation:
i.by the formula of (a+b)2=a²+2ab+b²
II. by the formula of (a-b)²=a²-2ab +b²
iii. 201×201=40401
Answered by
1
Answer:
i- (2x+3y)
= Using Identity (a+b)²=a²+2ab+b²
= (2x)²+2(2x)(3y)+(3y)²
= 4x²+12xy+9y²
ii- (3m-4n)
Using Identity (a-b)²=a²-2ab+b²
=(3m)²-2(3m)(4n)+4n²
= 9m²-24mn+16n²
iii- 201²
=Using Identity 1st
=(200+1)²
=(200)²+2(200)(1)+(1)²
=40000+400+1
=40401
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