Math, asked by vinaychauhan9900, 7 months ago

i. (2x – 5y) (2x – 5y) with method​

Answers

Answered by Anonymous
17

❥Answer-

( identity : (a-b)² = a²-2ab +b²)

 =  {(2x - 5y)}^{2}

 =  {(2x)}^{2}  - 2(2x)(5y) +  {(5y)}^{2}

 = 4 {x}^{2}  - 20xy + 25 {y}^{2}

Answered by mohammedsinan6499
0

Answer:

Answer-

( identity : (a-b)² = a²-2ab +b²)

= {(2x - 5y)}^{2}=(2x−5y)

2

= {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x)

2

−2(2x)(5y)+(5y)

2

= 4 {x}^{2} - 20xy + 25 {y}^{2}=4x

2

−20xy+25y

2

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