I(√3-1)/(√3+1)=a+b√3,then find the value of a&b.
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(√3-1)/(√3+1)=a+b√3
√3²-1=a+b√3
2=a+b√3.... ¹
a=b√3-2....²
put a in 1
2=a+b√3
2=b√3-2+b√3
4=2b√3
2=b√3
b=2/√3
put b in a=b√3-2
a=0
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I know this answer but I don't know
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