(i)36 - 1 = 35
(ii)35 – 3 = 32
(iii)32 – 5 = 27
(iv) 27 – 7 = 20
(v)20 – 9 = 11
(vi)11 – 11 = 0
Mrinal's partial work to calculate
the square root of 36 by repeated
subtraction method is given. Is
the work correct?
1 Yes, because each square
number is the sum of successive
odd prime numbers starting from
3.
2 No, because each square
number is the sum of successive
even natural numbers starting
from 2.
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yes this is correct because each square no. is the sum of successive odd prime no. starting from 3.
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