Question

i^_39
please help me it's a question no 3 of chapter 4 ex 1.1
class 11 th​

Answer 1

Answer:

i for -39. and -i for 39

Step-by-step explanation:

WKT

${i}^{2} = - 1$

${i}^{39} = {i}^{38} \times i$

$= { ({i}^{2}) }^{19} \times i$

$= {( - 1)}^{19} i$

$= - i$

$\frac{1}{ {i}^{39} } = - \frac{1}{i} = \frac{ {i}^{2} }{i} = i$

Hope it helps