Question

(i) 3x^2-4√3+4=0 find the nature of the roots of the following quadratic equation.if the real roots exist,find them​

Answer 1

ANSWER:

$3 {x}^{2} - 4 \sqrt{3} + 4 = 0$

$( \sqrt{3} \: x)^{2} - 2( \sqrt{3} )(2) + {(2)}^{2} = 0$

$( \sqrt{3} \: x - 2)^{2} = 0$

$takind \: square \: root \: on \: both \: sides$

$\sqrt{ ({ \sqrt{3} \: x - 4) }^{2} } = \sqrt{0}$

$\sqrt{3} \: x - 4 = 0$

$\sqrt{3} \: x = 4$

$x = \frac{4}{ \sqrt{3} }$

I hope it helps you. Please mark me as BRAINLIEST if you like.