Question

i) 449-9+4
iii) (15 + 15)- 17 - 13+(45 +17)
v) 1000 x 1 - 1000
vii) a-a=0
ix) a (b -c)=ab-ac
xi) 4 (5 x 8) = (4x 5) x 8​

Answer 1

Answer:

1. 449-9+4

BODMAS

449-9+4

=449-5

=444

2. (15+15)-17-13+(45+17)

BODMAS

30-17-13+62

= 30+62-17-13

= 92 -30

= 62

3. 1000×1-1000

BODMAS

1000×1 = 1000

Therefore, 1000-1000

= 0

4. a-a =0

If a = 1

1-1=0

5. a(b-c) = ab-ac

Expand the bracket

a×b - a×c= ab-ac

6. 4(5× 8)= (4×5)×8

BODMAS

4( 40)=(20)8

160 =160

Step-by-step explanation:

Using BODMAS

B- Bracket

O- Off

D- Division

M- Multiplication

A- Addition

S- Subtraction

helps to solve questions like this.

Hope it helps you!

#MizEevezi

Answer 2

Answer:

I think is help full to you