Question

(i) 48a2 - 243b2 factorisation
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Answer 1

Answer:

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Answer 2

Answer

We see that the two terms are not perfect squares. But both has '3' as common factor.

We see that the two terms are not perfect squares. But both has '3' as common factor.That is 48a

2−243b 2

=3[16a 2−81b 2 ]

=3[(4a) 2−(9b) 2 ] Again a 2−b 2

=(a+b)(a−b)

=3[(4a+9b)(4a−9b)]

=3(4a+9b)(4a−9b)