(i) 4a2 + 5b-6c + 6a2 + 7b + 9c + 2a2 -5b+ 4c
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4a²+5b−6c+6a²+7b+9c+2a²−5b+4c
=4a²+5b+−6c+6a²+7b+9c+2a²+−5b+4c
=(4a²+6a²+2a²)+(5b+7b+−5b)+(−6c+9c+4c)
=12a²+7b+7c
Answer:
=12a²+7b+7c
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