Math, asked by poonamshukla12pa5gcg, 10 months ago

(i) 4ab(a - b) – 6a2(b – b2) – 3b2(2a? –
a) + 2ab(b − a)​

Answers

Answered by mansoorisaniya1
2

Answer:

4a2b-4ab2-6a2b+6a2b2-6b2a2+3b2a+2ab2-2a2b

=4a2b-6a2b-2a2b-4ab2+3b2a+2ab2+6a2b2-6b2a2

=-4a2b+ab2

Step-by-step explanation:

all 2 after variable are square

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