Question

i) 4NH, + 50,- ii) 2NO + O, iii) 4NO, + 2H,0 + O, OʻH9 + OND yield = 50% yield = 70% - 2NO, 4HNO, yield = 64% Starting with 3 moles of NH, and excess of O, and H,0, find the moles of HNO, formed.​

Answer 1

Answer:

OʻH9 + OND yield = 50% yield = 70% - 2NO, 4HNO, yield = 64% Starting with 3 moles of NH, and excess of O, and H,0, find the moles of HNO, formed.