Question

i) 5 (6x + 1) = 3(-8+x)+2
please help me out with this problem​

Answer 1

Here we are given an equation 5 (6x + 1) = 3(-8+x) + 2

We have to solve the equation for x

In order to solve the equation we will have to rearrange the equation

First, we will open the brackets

5 (6x + 1) = 3(-8+x) + 2

  30x + 5 = - 24 + 3x + 2

     30x - 3x = -24 + 2 -5

             27x = -27

                 x = -1

Hence, the value of x will be -1

Answer 2

• As per the data given in the question, we have to find the value of the expression.

             Given data:- $5(6x+1)=3(-8+x)+2.$

             To find:- Value of the expression.

             Solution:-

• Here, we will use the below following steps to find a solution using the transposition method:

• Step 1:- we will Identify the variables and constants in the given simple equation.

• Step 2:-then we Simplify the equation in LHS and RHS.

• Step 3:- Transpose or shift the term on the other side to solve the equation further simplest.

• Step 4:- Simplify the equation using arithmetic operation as required that is mentioned in rule 1 or rule 2 of linear equations.

• Step 5:- Then the result will be the solution for the given linear equation. By using the transposition method. we get,

          $\Rightarrow 5(6 x+1)=3(-8+x)+2 \\\Rightarrow 30 x+5=-24+3 x+2 \\\Rightarrow 30 x-3 x=-24+2-5\\\Rightarrow 27 x=-27 \\\Rightarrow x=-1$

          Hence we will get the value $x=-1.$