Math, asked by subrata8837304194, 8 months ago

i) √5 + √80
ii) √50 - √32
iii)√363 - √147
iv) 2√12 + √75 - 7√3
v) √7 × √14
vi) 8√12 × 3√24​

Answers

Answered by medhansh88
2

Step-by-step explanation:

(i) \sqrt{5}  +  \sqrt{16 \times 5}  \\  =  \sqrt{5}  + 4 \sqrt{5}  \\  = 5 \sqrt{5}

(ii) \sqrt{50}  -  \sqrt{32}  \\  =  \sqrt{25 \times 2}  -  \sqrt{16 \times 2}  \\  = 5 \sqrt{2}  -  4\sqrt{2}  \\  = 1 \sqrt{2}

(iii) \sqrt{363}  -  \sqrt{147}  \\  =  \sqrt{121 \times 3}  -  \sqrt{49 \times 3}  \\  = 11 \sqrt{3}  - 7 \sqrt{3}  \\  = 4 \sqrt{3}

(iv)2 \sqrt{12}  +  \sqrt{75}  - 7 \sqrt{3}  \\  = 2 \sqrt{4 \times 3}  +  \sqrt{25 \times 3}  - 7 \sqrt{3}  \\  = 2 \times 2 \sqrt{3}  + 5 \sqrt{3}  - 7 \sqrt{3}  \\  = 4 \sqrt{3}  + 5 \sqrt{3}  - 7 \sqrt{3}  \\  = (4 + 5 - 7) \sqrt{3}  \\  = 2 \sqrt{3}

(v) \sqrt{7}  \times  \sqrt{14}  \\  =  \sqrt{98}  \\  =  \sqrt{49 \times 2}  \\  = 7 \sqrt{2}

(vi)8 \sqrt{12}  \times 3 \sqrt{24}  \\  = 8 \sqrt{4 \times 3}  \times 3 \sqrt{4 \times 6}  \\  = 16 \sqrt{3}  \times 6 \sqrt{6}  \\  = 96 \sqrt{18}  \\  = 96 \sqrt{9 \times 2}  \\  = 288 \sqrt{2}

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