Question

i)5 (x+4)= 35
ii)5x -3 = 3x - 5
iii)3 (x-3) = 5 (2x + 1)
find these answers by transposing method​

Answer 1

Answer with solution:

i) 5 (x+4)= 35

$➝ 5x + 20 = 35$

$➝ 5x = 35 - 20$

$➝ x = \frac{15}{5}$

$x = 3$

_____________

ii)5x -3 = 3x - 5

$➝ 5x - 15 = 3x - 5$

$➝ 5x - 3x = 15 - 5$

$➝ 2x = 10$

$➝ x = \frac{10}{2}$

$x = 5$

_____________

iii) 3 (x-3) = 5 (2x + 1)

$➝ 3x - 9 = 10x + 5$

$➝ 3x - 10x = 5 + 9$

$➝ x = \frac {14}{7}$

$➝x = 2$

Answer 2

$\huge\bf{{\color{indigo}{a}}{\color{maroon}{n}}{\red{s}}{\color{red}{w}}{\color{orange}{e}}{\color{gold}{r}}}$

$\small{ }$

To solve:

$\bf( \: i \: ) \: 5(x + 4) = 35 \\ \bf 5x + 20 = 35 \\ \bf 5x = 35 - 20 \\ \bf 5x = 15 \\ \bf x = \frac{15}{5} \\ \bf x = \underline{ \underline{3}}$

――――――――――――――――――――――――――――――――

$\bf ( \: ii \: ) \: 5x - 3 = 3x - 5 \\ \bf 5x - 3x = - 5 + 3 \\ \bf 2x = - 2 \\ \bf x = \frac{ - 2}{2} \\ \bf x = \underline{ \underline{ - 1}}$

――――――――――――――――――――――――――――――――

$\bf ( \: iii \: ) \: 3(x - 3) = 5(2x + 1) \\ \bf 3x - 9 = 10x + 5 \\ \bf 3x - 10x = 5 + 9 \\ \bf - 7x = 14 \\ \bf x = \frac{14}{ - 7} = \frac{ - 14}{7} \\ \bf x = \underline{ \underline{ - 2}}$

$\small{ }$

$\huge\bf{{\color{maroon}{Hope}}~{\color{red}{it}}~{\orange{helps..!!}}}$