Question

(i) 525 and 25 Paise x 13
(iii) * 899 and 50 Paise x 17
amount
3. Solve:
(ii) 507 and 75 Paise x 16
(iv) * 726 and 72 Paise x 19
of 35755.20 is given to the 13 women of 4101​

Answer 1

Answer:

$(i) 525 and 25 Paise x 13</p><p>(iii) * 899 and 50 Paise x 17</p><p>amount</p><p>3. Solve:</p><p>(ii) 507 and 75 Paise x 16</p><p>(iv) * 726 and 72 Paise x 19</p><p>of 35755.20 is given to the 13 women of 4101$

Answer 2

Step-by-step explanation:

Rs1=100p

Rs1=100p

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a Given, total amount =Rs605=605×100p

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a Given, total amount =Rs605=605×100p 100×3a+50×8a+25×16a=605×100

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a Given, total amount =Rs605=605×100p 100×3a+50×8a+25×16a=605×100

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a Given, total amount =Rs605=605×100p 100×3a+50×8a+25×16a=605×100 300a+400a+400a=60500

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a Given, total amount =Rs605=605×100p 100×3a+50×8a+25×16a=605×100 300a+400a+400a=60500

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a Given, total amount =Rs605=605×100p 100×3a+50×8a+25×16a=605×100 300a+400a+400a=60500 1100a=60500

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a Given, total amount =Rs605=605×100p 100×3a+50×8a+25×16a=605×100 300a+400a+400a=60500 1100a=60500 a=55

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a Given, total amount =Rs605=605×100p 100×3a+50×8a+25×16a=605×100 300a+400a+400a=60500 1100a=60500 a=55

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a Given, total amount =Rs605=605×100p 100×3a+50×8a+25×16a=605×100 300a+400a+400a=60500 1100a=60500 a=55 Hence, the number of Rs1=3a=165

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a Given, total amount =Rs605=605×100p 100×3a+50×8a+25×16a=605×100 300a+400a+400a=60500 1100a=60500 a=55 Hence, the number of Rs1=3a=165

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a Given, total amount =Rs605=605×100p 100×3a+50×8a+25×16a=605×100 300a+400a+400a=60500 1100a=60500 a=55 Hence, the number of Rs1=3a=165 50p=8a=440

Rs1=100p Let the number of 100p,50p,25p be 3a,8a,16a Given, total amount =Rs605=605×100p 100×3a+50×8a+25×16a=605×100 300a+400a+400a=60500 1100a=60500 a=55 Hence, the number of Rs1=3a=165 50p=8a=440 25p=16a=880