Question

{i}^{53} + {i}^{72} + {i}^{93} + {i}^{102} = 2i

please

Answer 1

Answer:

Step-by-step explanation:

(i^53 ) + (i^72) + (i^93) + (i^102) = 2i

LHS

= (i²)^26 . i + (i²)^36 + (i²)^46 . i + (i²)^51

= (-1)^26 . i + (-1)^36 + (-1)^46 . i + (-1)^51

= 1 . i + 1 + 1 . i - 1

= i + 1 + i - 1

= 2i

LHS = RHS

HENCE PROVED

HOPE IT HELPS U❇❇