Math, asked by jewellersveenus, 22 hours ago

i) 5ab,3a²b,7a⁴b²
ii) 2pq,4q²,8rp

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Answers

Answered by adyarashmi94
6

Step-by-step explanation:

1 5ab×3a²b×7a⁴b²

1 5ab×3a²b×7a⁴b²=105a⁷b⁴

1 5ab×3a²b×7a⁴b²=105a⁷b⁴2. 2pq ×4q²×8rp

1 5ab×3a²b×7a⁴b²=105a⁷b⁴2. 2pq ×4q²×8rp=64p²q³r

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