Math, asked by kkanchan2051, 24 days ago

(i) 8 men can do a piece of work in 28 days.
.. 1 man does the same in
days.
... 14 men do the same in
days =
days.​

Answers

Answered by aymankskhan
2

Answer :substitute the values to get your answer

Step-by-step explanation: The given details are,

A can do a piece of work in = 40 days

A’s 1 day work = 1/40

B can do a piece of work in = 45 days

B’s 1 day work = 1/45

(A+B)’s 1 day work together = 1/40 + 1/45

A+B’s 10 day work together = 10 (1/40 + 1/45)

= 10 ((9+8)/360) (by taking LCM for 40 and 45 which is 360)

= 10 × 17/360

= 17/36

Remaining work = 1 – 17/36

= (36 – 17)/36

= 19/36

∴ A can finish the remaining (19/36) work in = (19/36)/(1/40)

= (19/36) × 40

= 190/9

= 2119 days

Answered by prvnsharma666
4

Answer:

one man will do in 28×8 days and 14 men will do in 16 days

Step-by-step explanation:

8 men take 28 days. So one man will take more time. so one man will take 28×8 days

And 14 men will take (28×8)/14 =16 days

Hope you have understood

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