Question

(i) 8(x³y²z² + x²y³z² + x²y²z³)÷ 4x²y_z2​

Answer 1

Answer:

$\frac{8\left(x^3y^2z^2+x^2y^3z^2+x^2y^2z^3\right)}{4x^2y_z\cdot \:2}\\= \frac{8\left(x^3y^2z^2+x^2y^3z^2+x^2y^2z^3\right)}{8x^2y_z}\\= \frac{x^3y^2z^2+x^2y^3z^2+x^2y^2z^3}{x^2y_z}\\= \frac{y^2x^2z^2\left(x+y+z\right)}{x^2y_z}\\= \frac{y^2z^2\left(x+y+z\right)}{y_z}$

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