Question

I____________9384026088
p_________1234​

Answer 1

Answer:

Answer

We have,

LHS = (1−sin

2

θ)sec

2

θ

⇒LHS=cos

2

θsec

2

θ [∵1−sin

2

=cos

2

θ]

⇒LHS=cos

2

θ(

cos

2

θ

1

)

[∵secθ=

cosθ

1

]

⇒ LHS=1=RHS