Question

(i) 9x2 – 24x + k = 0
find the value of k for which the roots are real and equal in the equation​

Answer 1

Answer:

For equal roots D must be equal to 0.

then, D=0. ( Real and equal roots)

9x^2-24x+k=0

then comparing this equation with

ax^2+bx+c=0. , We have

a = 9. , b = -24. c= k

Then D = b^2-4ac=0

( -24)^2-4*9*k=0

576-36k=0

-36k=-576>>>>> 36k=576

k = 576/36=16

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Answer 2

SOLUTION:-

Given:

9x² - 24x +k=0

Therefore,

The roots of the quadratic equation;

Ax² + Bx + C=0 compared with.

Discriminate,D= b² -4ac

Now,

⚫A=9

⚫B=-24

⚫C= k

Therefore,

=) (-24)² - 4(9)(k)=0

=) 576 - 36k =0

=) 576= 36k

=) k= 576/36

=) k= 16

Thus,

The value of k is 16.

Hope it helps ☺️