Question

i)
( a +b)(b2+c2) = (ab +bc)2​

Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

(a+b)(b²+c²)=(ab+bc)²

ab²+ac²+b³+bc²=a²b²+b²c²+2ab²c

it is not equal

b³+ab²+a²b²+b²c+2ab²c+ac²+bc²=0

b²(b+a+a²+c+2ac)+c²(a+b)=0

b²(a+b)+b²(a²+c+2ac)+c²(a+b)=0

(b²+c²)(a+b)+b²(a²+c+2ac)=0

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