Question

(i) A (B-C) = (A x B) - (A C).
TE​

Answer 1

Step-by-step explanation:

{ x^[a(b - c)] / x^[b(a - c)] } / (x^b / x^a)^c = 1

If so, then the first thing that I'll do is simplify the exponents. Distributive properties in the first two and the exponent of an exponent is the product of the exponents in the third:

[ x^(ab - ac) / x^(ab - bc) ] / [x^(bc) / x^(ac)] = 1

Division of fractions is the same as the multiplication of the reciprocal:

[ x^(ab - ac) / x^(ab - bc) ] * [x^(ac) / x^(bc)] = 1

In each set of braces, the quotient of two numbers of the same base is the same as the differences in the exponents:

x^[(ab - ac) - (ab - bc)] * [x^(ac - bc)] = 1

and simplify:

x^(ab - ac - ab + bc) * x^(ac - bc) = 1

x^(-ac + bc) * x^(ac - bc) = 1

And finally, the product of two numbers of the same base is the same as the sum of the exponents:

x^[(-ac + bc) + (ac - bc)] = 1

and simplify:

x^(-ac + bc + ac - bc) = 1

x^(0) = 1

Anything to the 0 power is 1, so this is TRUE.

Hope This Helps plz make me brincly

Answer 2

Answer:

isme kya smjhana h sb kuch to explain ho hi rhkha h

.............................

A(B-C) = (A×B)-(A×C)

Let's understand ‍it with an example:

4(5-3) =(4×5)-(4×3)

= 20-13

= 7

SO 7 IS THE ANS OF THIS QUESTION