Question

I. A can do a piece of work in 25 days and B can
finish it in 20 days. They work together for 5 days
and then A leaves. In how many days will B finish
the remaining work?
​

Answer 1

Answer:

A's 1 day's work =251

Similarly, B's 1 day's work =201

A's and B's together 1 day's work

251+201=1004+1005=1004+5=1009

Their 5 day's work together = 5 x 1 day's work

1−10045=100100−10045=100100−45=10055

Now, this remaining work is done by B.

Let B takes x days to complete it.

201×x=10055⇒x=10055×20⇒x=555⇒x=11

Hence, B will finish the remaining work in 11 days.