(i)A=[cosαsinα−sinαcosα] then verify that A′A=I
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I PROVED IT BUT I THINK U POSTED INCOMPLETE MATRIX PLZ CHECK UR QUESTION AGAIN ITS NOT CLEAR
Step-by-step explanation:
*****************Hey dear *********************
Here is your answer....
A = { SIN (alpha - alpha)} = {sin 0} = 1
A' = 1
SO,
AA'=1 = I
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HOPE IT HELPS YOU .
THANKS..
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