Question

i) A Fair coin is tossed 5 times , find the probability that a) coin shows exactly
hree times head b) no head.
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Answer 1

a) 3/5

b) 1

this is the answer

Answer 2

Answer:

S=(H, T, H, T, H, H)

n(S)=6

let A be the event that shows head

A=(H, H, H)

n(A)=3

p(A)=n(A)/n(S)=3/6=1/2

let be be the event that shows no head

B=(T, T, T)

N(B)=3

p(B)=n(B)/n(S)=3/6=1/2