Question

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A farmer in a village had a total of 19 horses. The farmer had three sons. The farmer had written in his will how to distribute those horses after his death. 1/2 to the eldest child The number two child is 1/4 1/5 to the youngest child It was written to be distributed ... How will the allocation be possible? I

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Answer 1

Answer:

10 horses to the first son

5 horses to the second

and

4 horses to the third

Step-by-step explanation:

just add 1 to 19 then it will become 20

20/2=10

20/4=5

20/5=4

now.....proof

10+5+4=19

Answer 2

Answer:

• 1st son — half of the horses = 10
• 2nd son — one third of horses  = 5
• 3rd son — one ninth of horses  = 4

[MARK THE ANSWER AS BRAINLIEST]

Step-by-step explanation:

We have 19 horses to be divided among three sons with the ratio as given.

• 1st son — half of the horses (19/2)=9.5
• 2nd son — one third of horses (19/4)=4.75
• 3rd son — one ninth of horses (19/5)=3.8

Now all the results are in fraction so the horses cannot be distributed like this. What will the traveling mathematician do to solve it.

It’s simple. I will add my horse to the group of horses. So in total we have 20 horses now. Now let’s see the scenario again.

• 1st son — half of the horses (20/2) = 10
• 2nd son — one third of horses (20/4) = 5
• 3rd son — one ninth of horses (20/5) = 4

So in total 19 horses will get distributed among the three sons and I will take my horse and leave.