Physics, asked by aryansapre, 7 months ago

i) A force of 1500 N acts on the surface of area 15 cm 2 normally. What would
be the thrust and pressure on the surface?

Answers

Answered by nitingoswamilm10
3

Answer:

The Pressure = 100 Pa & The Thrust = 1500N

Explanation:

Thrust is the force acting normally on a surface.

According to the question,

∵ The force of 1500 N acts normally on the surface,

:. The Thrust = 1500N.

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Given,

Area (a) = 15 cm².

Thrust (T) = 1500N.

:. Pressure (P) = \frac{Thrust}{Area}

                       = \frac{T}{a}

                       = \frac{1500 N}{15 cm^{2} }

                       = 100 Pa  {Pa is Pascal (the S.I. unit of Pressure}

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Answered by farahfathima13052006
2

Answer:

Explanation:

THRUST IS THE FORCE ACTING ON A SURFACE IN THIS QUESTION 1500 N IS THE THRUST.

Thrust=1500N

Area=15cm2

pressure= thrust/area

            = 1500N/15cm2

           = 100 Pa

  ANSWER= 100Pa PRESSURE IS ACTED ON THE SURFACE WITH      1500N THRUST

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