(i) A force of 50kgf is applied to the smaller piston of a hydraulic machine. Neglecting friction, find the force exerted on the large piston, if the diameters of the pistons are 5 cm and 25cm respectively.
(ii) The diameter of neck and bottom of a bottle are 2cm and 10cm respectively. The bottle is completely filled with oil. If the cork in the neck is pressed in with a force of 1.2kgf, what force is exerted on the bottom of the bottle?
Answers
Answered by
141
in a hydraulic machine
force on larger piston/force on smaller piston=area of larger piston/area of smaller piston
let force on larger and smaller piston be F and f respectively
diameters of larger and smaller piston are 25cm and 5cm respectively
F/f=πR^2/πr^2=R^2/r^2
F/50=25*25/5*5
F=5*5*50=25*50=1250kgf
force on larger piston/force on smaller piston=area of larger piston/area of smaller piston
let force on larger and smaller piston be F and f respectively
diameters of larger and smaller piston are 25cm and 5cm respectively
F/f=πR^2/πr^2=R^2/r^2
F/50=25*25/5*5
F=5*5*50=25*50=1250kgf
Answered by
40
Answer:
F1 / F2 = A1 /A2
put F1 as 50, F2 as F2,A1 as 25,A2 as 625.
calculate...
f2
= (50×5×5)kgf = 1250 kgf
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