Question

(i) A girl of mass 40 kg stands on her feet of surface arca 80 cm (g = 10 m/s“). The pressure
exerted by her feet is
​

Answer 1

Answer:

5pascals

Explanation:

first you want find F=mg

F=40*10=400

next pressure=thrust/area

400/80=5pascal

Answer 2

The pressure  exerted by her feet is 50 kPa.

Explanation:

Given that,

Mass of the girl, m = 40 kg

Surface area of the feet, $A=80\ cm^2=0.008\ m^2$

We need to find the pressure  exerted by her feet. We know that the force acting per unit area is called pressure exerted by an object. It is given by :

$P=\dfrac{F}{A}\\\\P=\dfrac{mg}{A}\\\\P=\dfrac{40\ kg\times 10\ m/s^2}{0.008\ m^2}\\\\P=50000\ Pa$

or

P = 50 kPa

So, the pressure  exerted by her feet is 50 kPa. Hence, this is the required solution.

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