Question

I. A jar contains I rupee, 50 paise and 25 paise coins. There is a total of 10 coins in the jar such that number of 50 paise coins < number of 25 paise coins < number of I-rupee coins If one-fifth of the coins are of 50 paise, which of these is the ratio of I-rupee coins to the total number of coins?

Option I: 1:2

Option 2: 2:5

Option 3: 1:5

Option 4: 4:5

Answer 1

Answer:

the answer is 1:2

Step-by-step explanation:

50<25<1

for example we have 2 50 paisa coins and 3 25 paisa coins then we have 5 1 ruppe coins.

the ratios is 5:10

by simplyfying 1:2 is the answer

Answer 2

Answer:

The correct answer is Option 1: 1:2.

Step-by-step explanation:

Let the number of 50 paise coins be x, number of 25 paise coins be y, and number of I-rupee coins be z.

According to the problem statement, we have:

x + y + z = 10 (Total number of coins)

x < y < z (Number of 50 paise coins is less than number of 25 paise coins, which is less than number of I-rupee coins)

x = 10/5 = 2 (One-fifth of the coins are 50 paise coins)

Substituting x = 2 in the first equation, we get:

2 + y + z = 10

y + z = 8

Since y < z, the possible values of y and z are (2, 6), (3, 5), and (4, 4).

If y = 2 and z = 6, then the ratio of I-rupee coins to the total number of coins is z/(x + y + z) = 6/10 = 3/5, which is not one of the given options.

If y = 3 and z = 5, then the ratio of I-rupee coins to the total number of coins is z/(x + y + z) = 5/10 = 1/2, which matches with Option 1: 1:2.

If y = 4 and z = 4, then the number of 25 paise coins is equal to the number of I-rupee coins, which violates the given condition that y < z.

Therefore, the correct answer is Option 1: 1:2.

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