Question

(i) A lens produces an erect image of size 15 mm, when an object of size 6 mm isplaced 15 cm from its optical centre.(a) What is the nature of the lens?(b) Draw the relevant diagram to justify your answer to the above question(c) What can we say about the position of the object to get an image above?​

Answer 1

Answer:

By Magnification;

m=v/u=hi/ho

m=15/6mm

m=+2.5

This states image is virtual erect and enlarged

Given:

u=15cm

m=v/u

2.5=v/-15

v=2.5*-15

v=-37.5

Nature of lens ''convex lens.''

Position of object will be between focus and optic center.