Question

(i) A man is 3 times as old as his son. If the sum of the squares a
their ages is 1325, find the ages of the father and the son. [CBSE 2017​

Answer 1

men be x

son be y

x=3y

x²+y²=1325

(3y)²+y²=1325

10y²=1325

y²=1325/10

y=11.51

x=3(11.51)

x=34.53

Answer 2

Answer:

let the age of a son be X

then the age of the father be 3X

A/Q

(X)² +(3X)²=1325

X² +9X²=1325

10X²=1325

X²=1325/10

X²=625/2

X=25/√2

age of son is 25/√2

age of father 3X=(25/√2) ×3

=75/√2